What is expand 5cos(6(t-2))u(t-2) ?

The solution to expand 5cos(6(t-2))u(t-2) is 5tucos(6(t-2))-10ucos(6(t-2))

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expand 5cos(6(t-2))u(t-2)

expand

5 cos (6 (t - 2)) u (t - 2)

5 t u cos (6 (t - 2)) - 10 u cos (6 (t - 2))

Solution steps

5 cos (6 (t - 2)) u (t - 2)

= 5 u cos (6 (t - 2)) (t - 2)

Apply the distributive law:

a (b - c) = ab - a c

5 u cos (6 (t - 2)) (t - 2) = 5 u cos (6 (t - 2)) t - 5 u cos (6 (t - 2)) \cdot 2

= 5 u cos (6 (t - 2)) t - 5 u cos (6 (t - 2)) \cdot 2

Simplify

5 u cos (6 (t - 2)) t - 5 u cos (6 (t - 2)) \cdot 2 : 5 t u cos (6 (t - 2)) - 10 u cos (6 (t - 2))

= 5 t u cos (6 (t - 2)) - 10 u cos (6 (t - 2))

\frac{( x - 1 ) ( x - 2 ) ( x - 4 ) ( x - 5 )}{40}

\frac{4 x - 19}{4 ( x - 5 )}

\frac{2 x}{( x ^{2} + 1 ) ^{2} ( s + 1 )}

(6 x + \frac{5}{x}) (2 x + 3)

What is expand 5cos(6(t-2))u(t-2) ?
The solution to expand 5cos(6(t-2))u(t-2) is 5tucos(6(t-2))-10ucos(6(t-2))