What is expand (x(x-3)(x-4))/4 ?

The solution to expand (x(x-3)(x-4))/4 is (x^3)/4-(7x^2)/4+3x

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expand (x(x-3)(x-4))/4

expand

\frac{x ( x - 3 ) ( x - 4 )}{4}

\frac{x ^{3}}{4} - \frac{7 x ^{2}}{4} + 3 x

Solution steps

\frac{x ( x - 3 ) ( x - 4 )}{4}

Expand

x (x - 3) (x - 4) : x^{3} - 7 x^{2} + 12 x

= \frac{x ^{3} - 7 x ^{2} + 12 x}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 7 x ^{2} + 12 x}{4} = \frac{x ^{3}}{4} - \frac{7 x ^{2}}{4} + \frac{12 x}{4}

= \frac{x ^{3}}{4} - \frac{7 x ^{2}}{4} + \frac{12 x}{4}

Divide the numbers:

\frac{12}{4} = 3

= \frac{x ^{3}}{4} - \frac{7 x ^{2}}{4} + 3 x

\frac{1}{2} (y - \frac{1}{2} sin (2 y))

\frac{2 n + 1}{2 ( n + 1 ) ^{2}}

\frac{2 ( 2 z - 5 )}{45}

- \frac{- s ^{2} + 4}{( s ^{2} + 4 ) ^{2}} + \frac{s}{s ^{2} + 4}

(x - a^{\frac{1}{3}})^{3}

What is expand (x(x-3)(x-4))/4 ?
The solution to expand (x(x-3)(x-4))/4 is (x^3)/4-(7x^2)/4+3x