What is expand ((8t-2)^2)/9 ?

The solution to expand ((8t-2)^2)/9 is (64t^2)/9-(32t)/9+4/9

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expand ((8t-2)^2)/9

expand

\frac{( 8 t - 2 ) ^{2}}{9}

\frac{64 t ^{2}}{9} - \frac{32 t}{9} + \frac{4}{9}

Solution steps

\frac{( 8 t - 2 ) ^{2}}{9}

(8 t - 2)^{2} = 64 t^{2} - 32 t + 4

= \frac{64 t ^{2} - 32 t + 4}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{64 t ^{2} - 32 t + 4}{9} = \frac{64 t ^{2}}{9} - \frac{32 t}{9} + \frac{4}{9}

= \frac{64 t ^{2}}{9} - \frac{32 t}{9} + \frac{4}{9}

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What is expand ((8t-2)^2)/9 ?
The solution to expand ((8t-2)^2)/9 is (64t^2)/9-(32t)/9+4/9