What are the solutions to the equation 3t^2-16t+24=0 ?

The solutions to the equation 3t^2-16t+24=0 are t= 8/3+i(2sqrt(2))/3 ,t= 8/3-i(2sqrt(2))/3

Find the zeros of 3t^2-16t+24=0

The zeros of 3t^2-16t+24=0 are t= 8/3+i(2sqrt(2))/3 ,t= 8/3-i(2sqrt(2))/3

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3 t^{2} - 16 t + 24 = 0

t = \frac{8}{3} + i \frac{2 2}{3}, t = \frac{8}{3} - i \frac{2 2}{3}

Solution steps

3 t^{2} - 16 t + 24 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

Simplify

(- 16)^{2} - 4 \cdot 3 \cdot 24 : 42 i

t_{1, 2} = \frac{- ( - 16 ) \pm 4 2 i}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 16 ) + 4 2 i}{2 \cdot 3}, t_{2} = \frac{- ( - 16 ) - 4 2 i}{2 \cdot 3}

t = \frac{- ( - 16 ) + 4 2 i}{2 \cdot 3} : \frac{8}{3} + i \frac{2 2}{3}

t = \frac{- ( - 16 ) - 4 2 i}{2 \cdot 3} : \frac{8}{3} - i \frac{2 2}{3}

The solutions to the quadratic equation are:

t = \frac{8}{3} + i \frac{2 2}{3}, t = \frac{8}{3} - i \frac{2 2}{3}

- \frac{121 K - 241920}{756} > 0

\frac{3}{3} - \frac{1}{3}

5 x + 54 \geq 109

\frac{4}{\frac{1}{3}}

x + x + 1 = 2 x

What are the solutions to the equation 3t^2-16t+24=0 ?
The solutions to the equation 3t^2-16t+24=0 are t= 8/3+i(2sqrt(2))/3 ,t= 8/3-i(2sqrt(2))/3
Find the zeros of 3t^2-16t+24=0
The zeros of 3t^2-16t+24=0 are t= 8/3+i(2sqrt(2))/3 ,t= 8/3-i(2sqrt(2))/3