What is expand-2(ln(e^2-12)-4) ?

The solution to expand-2(ln(e^2-12)-4) is -2ln(e^2-12)+8

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expand-2(ln(e^2-12)-4)

expand

- 2 (ln (e^{2} - 12) - 4)

- 2 ln (e^{2} - 12) + 8

Solution steps

- 2 (ln (e^{2} - 12) - 4)

Apply the distributive law:

a (b - c) = ab - a c

a = - 2, b = ln (e^{2} - 12), c = 4

= - 2 ln (e^{2} - 12) - (- 2) \cdot 4

Apply minus-plus rules

- (- a) = a

= - 2 ln (e^{2} - 12) + 2 \cdot 4

Multiply the numbers:

2 \cdot 4 = 8

= - 2 ln (e^{2} - 12) + 8

\frac{1}{( ( s ^{2} + 1 ) ( s - 3 ) ( s - 6 ) )}

(n + 1) (\frac{n}{2}) (n + 1)

(s + p_{o}) (s + p_{1}) (s + p_{2})

(x - y) \frac{d}{d y} (x y + 2)

\frac{2 ( 2 + 10 )}{3}

What is expand-2(ln(e^2-12)-4) ?
The solution to expand-2(ln(e^2-12)-4) is -2ln(e^2-12)+8