What is expand (9x+16y=7,)(4y-3x=0) ?

The solution to expand (9x+16y=7,)(4y-3x=0) is 36xy-27x^2=0

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expand (9x+16y=7,)(4y-3x=0)

expand

(9 x + 16 y = 7,) (4 y - 3 x = 0)

36 x y - 27 x^{2} = 0

Solution steps

(9 x + 16 y = 7,) (4 y - 3 x = 0)

= (9 x + 16 \cdot 7 =, y) (4 y - 3 \cdot 0 = x)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 9 x, b = 16 y = 7,, c = 4 y, d = - 3 x = 0

9 x \cdot 4 y + 9 x (- 3 x = 0) + 16 y = 7, 4 y + 16 y = 7, (- 3 x = 0)

Apply minus-plus rules

+ (- a) = - a

9 \cdot 4 x y - 9 \cdot 3 xx = 0 + 16 y = 7, 4 y - 16 y = 7, 3 x = 0

Expand

9 \cdot 4 x y - 9 \cdot 3 xx : 36 x y - 27 x^{2}

36 x y - 27 x^{2} = 0

(p - 5)^{2}

f (a + 1, b - 2)

\frac{3}{( x - 1 ) ^{2}}

y d x + x (x^{2} y - 1) d y

2 (sin (x) + 1)

What is expand (9x+16y=7,)(4y-3x=0) ?
The solution to expand (9x+16y=7,)(4y-3x=0) is 36xy-27x^2=0