What is expand e^xln(e^x+1)-e^{-x}(e^x+1) ?

The solution to expand e^xln(e^x+1)-e^{-x}(e^x+1) is e^xln(e^x+1)-1-e^{-x}

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expand e^xln(e^x+1)-e^{-x}(e^x+1)

expand

e^{x} ln (e^{x} + 1) - e^{- x} (e^{x} + 1)

e^{x} ln (e^{x} + 1) - 1 - e^{- x}

Solution steps

e^{x} ln (e^{x} + 1) - e^{- x} (e^{x} + 1)

Expand

- e^{- x} (e^{x} + 1) : - 1 - e^{- x}

= e^{x} ln (e^{x} + 1) - 1 - e^{- x}

- \frac{2 ( e ^{x} - e ^{- x} )}{( e ^{x} + e ^{- x} ) ^{2}}

r \cdot w \cdot (1 - cos (w \cdot t), sin (w \cdot t))

\frac{( y + 1 ) ^{2}}{x}

tr (- x (x + 2) (x + 3))

x^{2} (\frac{x ^{2}}{2} - 2 y x)

What is expand e^xln(e^x+1)-e^{-x}(e^x+1) ?
The solution to expand e^xln(e^x+1)-e^{-x}(e^x+1) is e^xln(e^x+1)-1-e^{-x}