What is expand (3x+4)/(x(x+1)(x-1)) ?

The solution to expand (3x+4)/(x(x+1)(x-1)) is (3x+4)/(x^3-x)

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expand (3x+4)/(x(x+1)(x-1))

expand

\frac{3 x + 4}{x ( x + 1 ) ( x - 1 )}

\frac{3 x + 4}{x ^{3} - x}

Solution steps

\frac{3 x + 4}{x ( x + 1 ) ( x - 1 )}

Expand

x (x + 1) (x - 1) : x^{3} - x

= \frac{3 x + 4}{x ^{3} - x}

(2 + - y^{2} + y - 4)^{2}

16 (x - 1)^{2} + 16 (- \frac{1}{4} x + \frac{1}{4})^{2}

(2 x^{4} - 1)^{'} \cdot (5 x^{3} - 6) + (5 x^{3} - 6)^{'} \cdot (2 x^{4} - 1)

- K L + (U (t - \frac{e ^{x t} - 1}{x}))

(2 - 3) (2 + 46)

What is expand (3x+4)/(x(x+1)(x-1)) ?
The solution to expand (3x+4)/(x(x+1)(x-1)) is (3x+4)/(x^3-x)