What is 2(x^2+1)(sqrt(x^2+1))(x-1)^2 ?

The solution to 2(x^2+1)(sqrt(x^2+1))(x-1)^2 is 2(x^2+1)sqrt(x^2+1)(x-1)^2

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simplify 2(x^2+1)(sqrt(x^2+1))(x-1)^2

simplify

2 (x^{2} + 1) (x^{2} + 1) (x - 1)^{2}

2 (x^{2} + 1) x^{2} + 1 (x - 1)^{2}

Solution steps

2 (x^{2} + 1) (x^{2} + 1) (x - 1)^{2}

Apply rule:

(a) = a

(x^{2} + 1) = x^{2} + 1

= 2 (x^{2} + 1) x^{2} + 1 (x - 1)^{2}

(x - 1 + i y)^{3}

(- 2 sin (t) - t cos (t))^{2}

(x - 1 + i y)^{2}

\frac{- 2 x ^{2} - 22 x - 2}{3 ( x - 2 ) ( x + 1 ) ( x - 5 )}

(x + \frac{7}{2})^{2}

What is 2(x^2+1)(sqrt(x^2+1))(x-1)^2 ?
The solution to 2(x^2+1)(sqrt(x^2+1))(x-1)^2 is 2(x^2+1)sqrt(x^2+1)(x-1)^2