What is expand 1/(s+1)+2s+2+(1/(s+1)) ?

The solution to expand 1/(s+1)+2s+2+(1/(s+1)) is 2s+2/(s+1)+2

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expand 1/(s+1)+2s+2+(1/(s+1))

expand

\frac{1}{s + 1} + 2 s + 2 + (\frac{1}{s + 1})

2 s + \frac{2}{s + 1} + 2

Solution steps

\frac{1}{s + 1} + 2 s + 2 + (\frac{1}{s + 1})

Remove parentheses:

(a) = a

= \frac{1}{s + 1} + 2 s + 2 + \frac{1}{s + 1}

Group like terms

= 2 s + 1 \cdot \frac{1}{s + 1} + 1 \cdot \frac{1}{s + 1} + 2

Add similar elements:

1 \cdot \frac{1}{s + 1} + 1 \cdot \frac{1}{s + 1} = 2 \cdot \frac{1}{s + 1}

= 2 s + 2 \cdot \frac{1}{s + 1} + 2

2 \cdot \frac{1}{s + 1} = \frac{2}{s + 1}

= 2 s + \frac{2}{s + 1} + 2

(\frac{2}{x - 12} + 8 (100 - x)) (x - 12)

\frac{( 4 x ^{3} - 2 x ) ^{y}}{( 2 y - 1 ) e ^{y^{2}} - 2 e ^{3 y}}

δ (3 - 2 x)

(- 4 r + 4 r^{3} + 8 e^{2} r) (1 + 4 e^{2} r^{2})

(3 a - b = 1,) - (a + 2 b = - 1)

What is expand 1/(s+1)+2s+2+(1/(s+1)) ?
The solution to expand 1/(s+1)+2s+2+(1/(s+1)) is 2s+2/(s+1)+2