What is expand (t-3)\H(t-3) ?

The solution to expand (t-3)\H(t-3) is t\H(t-3)-3\H(t-3)

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expand (t-3)\H(t-3)

expand

(t - 3) H (t - 3)

t H (t - 3) - 3 H (t - 3)

Solution steps

(t - 3) H (t - 3)

= H (t - 3) (t - 3)

Apply the distributive law:

a (b - c) = ab - a c

a = H (t - 3), b = t, c = 3

= H (t - 3) t - H (t - 3) \cdot 3

= t H (t - 3) - 3 H (t - 3)

3 (\frac{1}{5} x + \frac{2}{5} y)

\frac{\partial}{\partial x} ((z) ((8 x + 2 y)^{4}))

(x^{3} + 89 + x^{3} + 9)^{2}

\frac{( 2 x ^{2} + x + 8 )}{( x ^{2} + 4 ) ^{2}}

\frac{y ^{'} ( z ) + y ( z ) ( 1 + r ( z ) )}{( 1 + z ) ( 1 + r ( z ) )}

What is expand (t-3)\H(t-3) ?
The solution to expand (t-3)\H(t-3) is t\H(t-3)-3\H(t-3)