What is 1/2 (-1/4 cos(4θ)-1/2 cos(2θ)) ?

The solution to 1/2 (-1/4 cos(4θ)-1/2 cos(2θ)) is (-1/4 cos(4θ)-1/2 cos(2θ))/2

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simplify 1/2 (-1/4 cos(4θ)-1/2 cos(2θ))

simplify

\frac{1}{2} (- \frac{1}{4} cos (4 θ) - \frac{1}{2} cos (2 θ))

\frac{- \frac{1}{4} cos ( 4 θ ) - \frac{1}{2} cos ( 2 θ )}{2}

Solution steps

\frac{1}{2} (- \frac{1}{4} cos (4 θ) - \frac{1}{2} cos (2 θ))

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( - \frac{1}{4} cos ( 4 θ ) - \frac{1}{2} cos ( 2 θ ) )}{2}

Apply rule:

1 \cdot a = a

1 \cdot (- \frac{1}{4} cos (4 θ) - \frac{1}{2} cos (2 θ)) = (- \frac{1}{4} cos (4 θ) - \frac{1}{2} cos (2 θ))

= \frac{- \frac{1}{4} cos ( 4 θ ) - \frac{1}{2} cos ( 2 θ )}{2}

(- 1, cos (t)) \cdot (2 sin (t), 3 π - 3 t)

\frac{( 3 x + 2 ) ^{2}}{4 ( x + 2 ) ^{2}}

(- 10 + 5) x

\frac{2 x + 15 + 2}{2 ( x - 3 ) ( x + 10 )}

What is 1/2 (-1/4 cos(4θ)-1/2 cos(2θ)) ?
The solution to 1/2 (-1/4 cos(4θ)-1/2 cos(2θ)) is (-1/4 cos(4θ)-1/2 cos(2θ))/2