What is expand (x^3-3x^2)/((x-1)^3) ?

The solution to expand (x^3-3x^2)/((x-1)^3) is (x^3-3x^2)/(x^3-3x^2+3x-1)

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expand (x^3-3x^2)/((x-1)^3)

expand

\frac{x ^{3} - 3 x ^{2}}{( x - 1 ) ^{3}}

\frac{x ^{3} - 3 x ^{2}}{x ^{3} - 3 x ^{2} + 3 x - 1}

Solution steps

\frac{x ^{3} - 3 x ^{2}}{( x - 1 ) ^{3}}

(x - 1)^{3} = x^{3} - 3 x^{2} + 3 x - 1

= \frac{x ^{3} - 3 x ^{2}}{x ^{3} - 3 x ^{2} + 3 x - 1}

(lo g_{10} (x)) (x + 1) (x + 2) (x + 3)

\frac{x ( x - y ln ( x ) )}{y ( y - x ln ( y ) )}

7 (10 + 3)

\frac{1}{s ( 6 s + 1 )}

\frac{1 0 ^{2}}{1 0 ^{3}}

What is expand (x^3-3x^2)/((x-1)^3) ?
The solution to expand (x^3-3x^2)/((x-1)^3) is (x^3-3x^2)/(x^3-3x^2+3x-1)