What is expand (sec(θ)+tan(θ))cos(θ) ?

The solution to expand (sec(θ)+tan(θ))cos(θ) is sin(θ)+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (sec(θ)+tan(θ))cos(θ)

expand

(sec (θ) + tan (θ)) cos (θ)

sin (θ) + 1

Solution steps

(sec (θ) + tan (θ)) cos (θ)

= cos (θ) (sec (θ) + tan (θ))

Apply the distributive law:

a (b + c) = ab + a c

cos (θ) (sec (θ) + tan (θ)) = cos (θ) sec (θ) + cos (θ) tan (θ)

= cos (θ) sec (θ) + cos (θ) tan (θ)

Simplify

cos (θ) sec (θ) + cos (θ) tan (θ) : sin (θ) + 1

= sin (θ) + 1

\frac{( x + 2 ) ^{3} ( 9 x - 2 )}{12}

\frac{( 4 x + 12 ) ^{2}}{4} + \frac{( y - 4 ) ^{2}}{4}

(t - a) (H (t - a) - H (t - b))

\frac{( 8 - x )}{( x + 2 ) ^{2}}

What is expand (sec(θ)+tan(θ))cos(θ) ?
The solution to expand (sec(θ)+tan(θ))cos(θ) is sin(θ)+1