What is expand 4x(6/x+(x-3)/4 =2)4x ?

The solution to expand 4x(6/x+(x-3)/4 =2)4x is 4x^3-12x^2+96x=2

Popular >

expand 4x(6/x+(x-3)/4 =2)4x

expand

4 x (\frac{6}{x} + \frac{x - 3}{4} = 2) 4 x

4 x^{3} - 12 x^{2} + 96 x = 2

Solution steps

4 x (\frac{6}{x} + \frac{x - 3}{4} = 2) \cdot 4 x

= 4 \cdot 4 xx (\frac{6}{x} + 2 = \frac{x - 3}{4})

Apply the distributive law:

a (b + c) = ab + a c

a = 4 x \cdot 4 x, b = \frac{6}{x}, c = \frac{x - 3}{4} = 2

4 x \cdot 4 x \frac{6}{x} + 4 x \cdot 4 x \frac{x - 3}{4} = 2

4 \cdot 4 \cdot \frac{6}{x} xx + 4 \cdot 4 xx \frac{x - 3}{4} = 2

Expand

4 \cdot 4 \cdot \frac{6}{x} xx + 4 \cdot 4 xx \frac{x - 3}{4} : 4 x^{3} - 12 x^{2} + 96 x

4 x^{3} - 12 x^{2} + 96 x = 2

5 (11 - 6)

2 x (1 + y^{2}) d x - y (1 + 2 x^{2}) d y

(-) (x - 1) (3 - x)

\frac{x ^{2} - 36 e ^{- 4 π x} + 45}{( x ^{2} + 9 ) ( x ^{2} + 33 )}

(x - y - 1)^{2}

What is expand 4x(6/x+(x-3)/4 =2)4x ?
The solution to expand 4x(6/x+(x-3)/4 =2)4x is 4x^3-12x^2+96x=2