What is expand (n(n-1)(n-2))/6 ?

The solution to expand (n(n-1)(n-2))/6 is (n^3)/6-(n^2)/2+n/3

Popular >

expand (n(n-1)(n-2))/6

expand

\frac{n ( n - 1 ) ( n - 2 )}{6}

\frac{n ^{3}}{6} - \frac{n ^{2}}{2} + \frac{n}{3}

Solution steps

\frac{n ( n - 1 ) ( n - 2 )}{6}

Expand

n (n - 1) (n - 2) : n^{3} - 3 n^{2} + 2 n

= \frac{n ^{3} - 3 n ^{2} + 2 n}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{3} - 3 n ^{2} + 2 n}{6} = \frac{n ^{3}}{6} - \frac{3 n ^{2}}{6} + \frac{2 n}{6}

= \frac{n ^{3}}{6} - \frac{3 n ^{2}}{6} + \frac{2 n}{6}

Cancel

\frac{3 n ^{2}}{6} : \frac{n ^{2}}{2}

= \frac{n ^{3}}{6} - \frac{n ^{2}}{2} + \frac{2 n}{6}

Cancel

\frac{2 n}{6} : \frac{n}{3}

= \frac{n ^{3}}{6} - \frac{n ^{2}}{2} + \frac{n}{3}

\frac{2 s ^{2} + 79 s + 308}{( s - 4 ) ( s ^{2} + 10 s + 26 )}

(2 x + 1) \cdot (x - \frac{1}{2})

- \frac{9025}{( 99 t - 95 ) ^{2}}

(a - b - c cos (x))^{2}

(x^{3} e^{9 x} + 2) x

What is expand (n(n-1)(n-2))/6 ?
The solution to expand (n(n-1)(n-2))/6 is (n^3)/6-(n^2)/2+n/3