What is (2+i)^2-(3-i)^2 ?

The solution to (2+i)^2-(3-i)^2 is -5+10i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (2+i)^2-(3-i)^2

simplify

(2 + i)^{2} - (3 - i)^{2}

- 5 + 10 i

Solution steps

(2 + i)^{2} - (3 - i)^{2}

(2 + i)^{2} = 4 i + 3

(3 - i)^{2} = - 6 i + 8

= 4 i + 3 - (- 6 i + 8)

Expand

- (- 6 i + 8) : 6 i - 8

= 4 i + 3 + 6 i - 8

Group like terms

= 4 i + 6 i + 3 - 8

Add similar elements:

4 i + 6 i = 10 i

= 10 i + 3 - 8

Subtract the numbers:

3 - 8 = - 5

= 10 i - 5

Rewrite in standard complex form:

- 5 + 10 i

= - 5 + 10 i

ln (e^{2})

6 x^{2} - 11 x + 3

1 2^{- \frac{1}{3}}

x^{2} - 9 x + 19 = x - 5