What is expand (2x+1)/((x-4)(x+2)^2) ?

The solution to expand (2x+1)/((x-4)(x+2)^2) is (2x+1)/(x^3-12x-16)

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expand (2x+1)/((x-4)(x+2)^2)

expand

\frac{2 x + 1}{( x - 4 ) ( x + 2 ) ^{2}}

\frac{2 x + 1}{x ^{3} - 12 x - 16}

Solution steps

\frac{2 x + 1}{( x - 4 ) ( x + 2 ) ^{2}}

(x + 2)^{2} = x^{2} + 4 x + 4

= \frac{2 x + 1}{( x - 4 ) ( x ^{2} + 4 x + 4 )}

Expand

(x - 4) (x^{2} + 4 x + 4) : x^{3} - 12 x - 16

= \frac{2 x + 1}{x ^{3} - 12 x - 16}

((6) (2 a e^{a x} + a^{2} e^{a x} x)) (x e^{a x})

1 + 2 t^{2} + 9 t^{4}

\frac{d}{d P} ((V^{1}) (q^{4} + P))

(t) \cdot (1 - t)

(y \cdot e^{x} + x \cdot y \cdot e^{x} + 1) d x + (x \cdot e^{x}) d y

What is expand (2x+1)/((x-4)(x+2)^2) ?
The solution to expand (2x+1)/((x-4)(x+2)^2) is (2x+1)/(x^3-12x-16)