What is expand (L^2x^2-3Lx^3+2x^4)/(L^3) ?

The solution to expand (L^2x^2-3Lx^3+2x^4)/(L^3) is (x^2)/L-(3x^3)/(L^2)+(2x^4)/(L^3)

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expand (L^2x^2-3Lx^3+2x^4)/(L^3)

expand

\frac{L ^{2} x ^{2} - 3 L x ^{3} + 2 x ^{4}}{L ^{3}}

\frac{x ^{2}}{L} - \frac{3 x ^{3}}{L ^{2}} + \frac{2 x ^{4}}{L ^{3}}

Solution steps

\frac{L ^{2} x ^{2} - 3 L x ^{3} + 2 x ^{4}}{L ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{L ^{2} x ^{2} - 3 L x ^{3} + 2 x ^{4}}{L ^{3}} = \frac{L ^{2} x ^{2}}{L ^{3}} - \frac{3 L x ^{3}}{L ^{3}} + \frac{2 x ^{4}}{L ^{3}}

= \frac{L ^{2} x ^{2}}{L ^{3}} - \frac{3 L x ^{3}}{L ^{3}} + \frac{2 x ^{4}}{L ^{3}}

Cancel

\frac{L ^{2} x ^{2}}{L ^{3}} : \frac{x ^{2}}{L}

= \frac{x ^{2}}{L} - \frac{3 L x ^{3}}{L ^{3}} + \frac{2 x ^{4}}{L ^{3}}

Cancel

\frac{3 L x ^{3}}{L ^{3}} : \frac{3 x ^{3}}{L ^{2}}

= \frac{x ^{2}}{L} - \frac{3 x ^{3}}{L ^{2}} + \frac{2 x ^{4}}{L ^{3}}

\frac{( a - b ) ^{2}}{( a + b )}

\frac{2}{9 + 4 x}

(x^{3} - 2) (sec^{2} (x))

e^{in (s e c (θ) + t a n (θ))}

What is expand (L^2x^2-3Lx^3+2x^4)/(L^3) ?
The solution to expand (L^2x^2-3Lx^3+2x^4)/(L^3) is (x^2)/L-(3x^3)/(L^2)+(2x^4)/(L^3)