What is expand (3x^2-6x-7)/((x+4)(x-3)) ?

The solution to expand (3x^2-6x-7)/((x+4)(x-3)) is (3x^2-6x-7)/(x^2+x-12)

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expand (3x^2-6x-7)/((x+4)(x-3))

expand

\frac{3 x ^{2} - 6 x - 7}{( x + 4 ) ( x - 3 )}

\frac{3 x ^{2} - 6 x - 7}{x ^{2} + x - 12}

Solution steps

\frac{3 x ^{2} - 6 x - 7}{( x + 4 ) ( x - 3 )}

Expand

(x + 4) (x - 3) : x^{2} + x - 12

= \frac{3 x ^{2} - 6 x - 7}{x ^{2} + x - 12}

(x^{2} - 2) (x + 1)

\frac{2}{( s ^{2} + 4 ) s}

(x + x^{3} sin (2 y)) d y - 2 y d x

\frac{( s + 2 ) ( s + 6 )}{s ( s + 1 ) ( s + 5 ) ( s + 10 )}

\frac{\partial}{\partial y} ((g (y, x)) (x + y))

What is expand (3x^2-6x-7)/((x+4)(x-3)) ?
The solution to expand (3x^2-6x-7)/((x+4)(x-3)) is (3x^2-6x-7)/(x^2+x-12)