What is expand (5X-65)/((X-4)(X-9)) ?

The solution to expand (5X-65)/((X-4)(X-9)) is (5X-65)/(X^2-13X+36)

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expand (5X-65)/((X-4)(X-9))

expand

\frac{5 X - 65}{( X - 4 ) ( X - 9 )}

\frac{5 X - 65}{X ^{2} - 13 X + 36}

Solution steps

\frac{5 X - 65}{( X - 4 ) ( X - 9 )}

Expand

(X - 4) (X - 9) : X^{2} - 13 X + 36

= \frac{5 X - 65}{X ^{2} - 13 X + 36}

(t + 3)^{2} H^{5}

(3 e^{3 t} - 3 e^{t}) (1.5 e^{- 3 t} - 0.5 e^{- t})

2 π (\frac{56}{3} - 83)

(x^{2} + 9) (x - 4 - 5)

\frac{( 3 x ^{2} + 7 x )}{( x - 1 ) ( x ^{2} + 4 x + 5 )}

What is expand (5X-65)/((X-4)(X-9)) ?
The solution to expand (5X-65)/((X-4)(X-9)) is (5X-65)/(X^2-13X+36)