What is the d/(dt)((C)(8000+2x(C,t))) ?

The d/(dt)((C)(8000+2x(C,t))) is C(0+2 d/(dt)({x}(C,t)))

What is the first d/(dt)((C)(8000+2x(C,t))) ?

The first d/(dt)((C)(8000+2x(C,t))) is C(0+2 d/(dt)({x}(C,t)))

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\frac{d}{d t} ((C) (8000 + 2 x (C, t)))

C (0 + 2 \frac{d}{d t} (x (C, t)))

Solution steps

\frac{d}{d t} ((C) (8000 + 2 x (C, t)))

Treat

C

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= C \frac{d}{d t} (8000 + 2 x (C, t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= C (\frac{d}{d t} (8000) + \frac{d}{d t} (2 x (C, t)))

\frac{d}{d t} (8000) = 0

\frac{d}{d t} (2 x (C, t)) = 2 \frac{d}{d t} (x (C, t))

= C (0 + 2 \frac{d}{d t} (x (C, t)))

(5 x^{2} + x + 1) e^{x}

(3 x + 2) (\frac{( 2 x - 3 ) ( 4 x - 2 )}{2})

(D + 6) (5 x - (D - 4) = 0)

\frac{A ( x ) B ( y )}{( x + y ) ^{2}}

x^{2} y^{''} (x) - x y^{'} (x) + (1 - x) y

What is the d/(dt)((C)(8000+2x(C,t))) ?
The d/(dt)((C)(8000+2x(C,t))) is C(0+2 d/(dt)({x}(C,t)))
What is the first d/(dt)((C)(8000+2x(C,t))) ?
The first d/(dt)((C)(8000+2x(C,t))) is C(0+2 d/(dt)({x}(C,t)))