What is 1/2 (log_{10}(x)y-log_{10}(7)) ?

The solution to 1/2 (log_{10}(x)y-log_{10}(7)) is 1/2 log_{10}(x)y-1/2 log_{10}(7)

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simplify 1/2 (log_{10}(x)y-log_{10}(7))

simplify

\frac{1}{2} (lo g_{10} (x) y - lo g_{10} (7))

\frac{1}{2} lo g_{10} (x) y - \frac{1}{2} lo g_{10} (7)

Solution steps

\frac{1}{2} (lo g_{10} (x) y - lo g_{10} (7))

Apply the distributive law:

a (b - c) = ab - a c

\frac{1}{2} (lo g_{10} (x) y - lo g_{10} (7)) = \frac{1}{2} lo g_{10} (x) y - \frac{1}{2} lo g_{10} (7)

= \frac{1}{2} lo g_{10} (x) y - \frac{1}{2} lo g_{10} (7)

(sin (m) - tan (m)) (cos (m) - cot (m))

\frac{x ^{2} + x + 4}{( x + 2 ) ( x ^{2} - 9 x + 2 )}

(x - \frac{1}{2}) (x - \frac{1}{2})

\frac{( x - 2 ) ( x + 2 )}{x - 4}

(x^{2}) ((cos^{2} (x)) + sin (x))

What is 1/2 (log_{10}(x)y-log_{10}(7)) ?
The solution to 1/2 (log_{10}(x)y-log_{10}(7)) is 1/2 log_{10}(x)y-1/2 log_{10}(7)