What is expand (x^2+6\circ x^2-1)(x) ?

The solution to expand (x^2+6\circ x^2-1)(x) is x^3+6\circ x^3-x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^2+6\circ x^2-1)(x)

expand

(x^{2} + 6 \circ x^{2} - 1) (x)

x^{3} + 6 \circ x^{3} - x

Solution steps

(x^{2} + 6 \circ x^{2} - 1) (x)

= (x) (x^{2} + 6 \circ x^{2} - 1)

Distribute parentheses

= (x) x^{2} + (x) \cdot 6 \circ x^{2} + (x) (- 1)

Apply minus-plus rules

+ (- a) = - a

= x^{2} (x) + 6 \circ x^{2} (x) - 1 \cdot (x)

Simplify

x^{2} (x) + 6 \circ x^{2} (x) - 1 \cdot (x) : x^{3} + 6 \circ x^{3} - x

= x^{3} + 6 \circ x^{3} - x

(x + \frac{1}{2}) (x + 1)

\frac{1 - x ^{2}}{3 - x ^{- 1}}

\frac{3 ( 3 sin ( 2 t ) - 2 cos ( 2 t ) )}{26}

(a x + b + 6 + 2 x) \cdot (x + 4 x^{2})

Z^{20} e - 2 x d x + Z^{103} x (x^{2} - 1) 5 d x

What is expand (x^2+6\circ x^2-1)(x) ?
The solution to expand (x^2+6\circ x^2-1)(x) is x^3+6\circ x^3-x