What is expand ((-1)^nn!)/(4^n(n+3)) ?

The solution to expand ((-1)^nn!)/(4^n(n+3)) is ((-1)^nn!)/(4^nn+3*4^n)

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expand ((-1)^nn!)/(4^n(n+3))

expand

\frac{( - 1 ) ^{n} n !}{4 ^{n} ( n + 3 )}

\frac{( - 1 ) ^{n} n !}{4 ^{n} n + 3 \cdot 4 ^{n}}

Solution steps

\frac{( - 1 ) ^{n} n !}{4 ^{n} ( n + 3 )}

Expand

4^{n} (n + 3) : 4^{n} n + 3 \cdot 4^{n}

= \frac{( - 1 ) ^{n} n !}{4 ^{n} n + 3 \cdot 4 ^{n}}

y (6 - 3 y - 2 z)^{2}

(1 + (x + i y)^{3})^{2}

2 s^{2} e^{2 t} (1 - 3 s^{3} e^{- 3 t}) + 9 s^{3} e^{t}

(3 - \frac{x}{47829669})^{20}

e^{x t - t} \cdot (U e^{x t} - Ux t - U)

What is expand ((-1)^nn!)/(4^n(n+3)) ?
The solution to expand ((-1)^nn!)/(4^n(n+3)) is ((-1)^nn!)/(4^nn+3*4^n)