What is expand t(e^{-3t}+e^{-2t}) ?

The solution to expand t(e^{-3t}+e^{-2t}) is e^{-3t}t+e^{-2t}t

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expand t(e^{-3t}+e^{-2t})

expand

t (e^{- 3 t} + e^{- 2 t})

e^{- 3 t} t + e^{- 2 t} t

Solution steps

t (e^{- 3 t} + e^{- 2 t})

Apply the distributive law:

a (b + c) = ab + a c

a = t, b = e^{- 3 t}, c = e^{- 2 t}

= t e^{- 3 t} + t e^{- 2 t}

= e^{- 3 t} t + e^{- 2 t} t

5 (- 8 + 3)

4 (2 x cos (2 t) - 2 y sin (2 t))

(7^{\frac{1}{3}} - 4^{\frac{1}{3}}) (7^{\frac{1}{3}} + 4^{\frac{1}{3}})

\frac{7.3 ( 1 + 467.4 s )}{s ( 1 + 467.4 s ) + 0.342}

x (0 = 514000 x^{3} + 40240 x^{2} + 40390.4 - 559049.7)

What is expand t(e^{-3t}+e^{-2t}) ?
The solution to expand t(e^{-3t}+e^{-2t}) is e^{-3t}t+e^{-2t}t