What is expand (2xy+z^2)(3cos(t)) ?

The solution to expand (2xy+z^2)(3cos(t)) is 6xycos(t)+3z^2cos(t)

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expand (2xy+z^2)(3cos(t))

expand

(2 x y + z^{2}) (3 cos (t))

6 x y cos (t) + 3 z^{2} cos (t)

Solution steps

(2 x y + z^{2}) (3 cos (t))

= (3 cos (t)) (2 x y + z^{2})

Apply the distributive law:

a (b + c) = ab + a c

(3 cos (t)) (2 x y + z^{2}) = 3 cos (t) \cdot 2 x y + 3 cos (t) z^{2}

= 3 cos (t) \cdot 2 x y + 3 cos (t) z^{2}

Simplify

3 cos (t) \cdot 2 x y + 3 cos (t) z^{2} : 6 x y cos (t) + 3 z^{2} cos (t)

= 6 x y cos (t) + 3 z^{2} cos (t)

(\frac{7}{x ^{3}} + 5 x^{5})^{5}

(x) \cdot (x - 4)

100.53 (t - sin (t))

[s \cdot y - d \cdot k, y - d \cdot k] + d i v i d e [k, y - d \cdot k] (1 - s) d - s

\frac{80 ( 0.6 x cos ( 0.6 x ) - sin ( 0.6 x ) )}{x ^{2}}

What is expand (2xy+z^2)(3cos(t)) ?
The solution to expand (2xy+z^2)(3cos(t)) is 6xycos(t)+3z^2cos(t)