What is expand ((3x-3)/2)*((x-1)/3) ?

The solution to expand ((3x-3)/2)*((x-1)/3) is (x^2)/2-x+1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((3x-3)/2)*((x-1)/3)

expand

(\frac{3 x - 3}{2}) \cdot (\frac{x - 1}{3})

\frac{x ^{2}}{2} - x + \frac{1}{2}

Solution steps

(\frac{3 x - 3}{2}) (\frac{x - 1}{3})

Remove parentheses:

(a) = a

= \frac{3 x - 3}{2} \cdot \frac{x - 1}{3}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 3 x - 3 ) ( x - 1 )}{2 \cdot 3}

Multiply the numbers:

2 \cdot 3 = 6

= \frac{( 3 x - 3 ) ( x - 1 )}{6}

Factor

(3 x - 3) (x - 1) : 3 (x - 1)^{2}

= \frac{3 ( x - 1 ) ^{2}}{6}

Cancel the common factor:

3

= \frac{( x - 1 ) ^{2}}{2}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{x ^{2} - 2 x + 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 2 x + 1}{2} = \frac{x ^{2}}{2} - \frac{2 x}{2} + \frac{1}{2}

= \frac{x ^{2}}{2} - \frac{2 x}{2} + \frac{1}{2}

Divide the numbers:

\frac{2}{2} = 1

= \frac{x ^{2}}{2} - x + \frac{1}{2}

e^{x} sin (3 x) - e^{x} cos (3 x) (D^{2} - 2 D + 10)

, (- 3 + 8 i) (6 + 2 i)

7 (- 9 - 715)

\frac{2000 s - 2000 e ^{- s}}{s ^{2} ( s ^{2} + 200 s + 200 )}

x - (5 + 3 x - (5 x - (6 + x)) = - 3)

What is expand ((3x-3)/2)*((x-1)/3) ?
The solution to expand ((3x-3)/2)*((x-1)/3) is (x^2)/2-x+1/2