What is (x+5)(3x-2)(x+2+i)(x-2+i) ?

The solution to (x+5)(3x-2)(x+2+i)(x-2+i) is (x+5)(3x-2)(x^2-5)+(x+5)(3x-2)*2xi

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simplify (x+5)(3x-2)(x+2+i)(x-2+i)

simplify

(x + 5) (3 x - 2) (x + 2 + i) (x - 2 + i)

(x + 5) (3 x - 2) (x^{2} - 5) + (x + 5) (3 x - 2) \cdot 2 x i

Solution steps

(x + 5) (3 x - 2) (x + 2 + i) (x - 2 + i)

Apply complex arithmetic rule:

(a + bi) (c + d i) = (a c - b d) + (a d + b c) i

= (x + 5) (3 x - 2) (((x + 2) (x - 2) - 1 \cdot 1) + ((x + 2) \cdot 1 + 1 \cdot (x - 2)) i)

Simplify

((x + 2) (x - 2) - 1 \cdot 1) + ((x + 2) \cdot 1 + 1 \cdot (x - 2)) i : (x^{2} - 5) + 2 x i

= (x + 5) (3 x - 2) ((x^{2} - 5) + 2 x i)

Distribute parentheses

= (x + 5) (3 x - 2) (x^{2} - 5) + (x + 5) (3 x - 2) \cdot 2 x i

4 (6 x - 5 y = 28)

\frac{( ( 4 - x ^{2} ) ^{4} )}{2}

(x + 1) (\frac{2 x}{x + 1} + 1)

\frac{5 x + 13}{( 2 x + 1 ) ( x + 4 )}

lo g_{10} (\frac{a - b}{a + b})

What is (x+5)(3x-2)(x+2+i)(x-2+i) ?
The solution to (x+5)(3x-2)(x+2+i)(x-2+i) is (x+5)(3x-2)(x^2-5)+(x+5)(3x-2)*2xi