What are the solutions to the equation x(x+1)=1.5x^2 ?

The solutions to the equation x(x+1)=1.5x^2 are x=0,x=2

Find the zeros of x(x+1)=1.5x^2

The zeros of x(x+1)=1.5x^2 are x=0,x=2

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x (x + 1) = 1.5 x^{2}

x = 0, x = 2

Solution steps

x (x + 1) = 1.5 x^{2}

Move

1.5 x^{2}

to the left side

x (x + 1) - 1.5 x^{2} = 0

Factor

x (x + 1) - 1.5 x^{2} : - x (0.5 x - 1)

- x (0.5 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 0.5 x - 1 = 0

Solve

0.5 x - 1 = 0 : x = 2

The solutions to the quadratic equation are:

x = 0, x = 2

- 5 x + 4 (2 x + 2) = - 1

3 (1 - 2 x) = \frac{1}{4} (6 x + 9)

- 4 ∣ 2 w + 6 ∣ = - 32

\frac{2}{5} + \frac{3}{2}

\frac{2}{3} x - 4 = \frac{2}{5}

What are the solutions to the equation x(x+1)=1.5x^2 ?
The solutions to the equation x(x+1)=1.5x^2 are x=0,x=2
Find the zeros of x(x+1)=1.5x^2
The zeros of x(x+1)=1.5x^2 are x=0,x=2