What is (\partial)/(\partial x)((y)(10-y-2x)) ?

The answer to (\partial)/(\partial x)((y)(10-y-2x)) is -2y

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(\partial)/(\partial x)((y)(10-y-2x))

\frac{\partial}{\partial x} ((y) (10 - y - 2 x))

- 2 y

Solution steps

\frac{\partial}{\partial x} ((y) (10 - y - 2 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (10 - y - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (\frac{\partial}{\partial x} (10) - \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (2 x))

\frac{\partial}{\partial x} (10) = 0

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (2 x) = 2

= y (0 - 0 - 2)

Simplify

= - 2 y

\frac{e ^{- 2 π s} - s}{s ( s ^{2} + 1 ) ( s ^{2} + 4 )}

x^{3} + 3^{3}

(- 4 - 9 i)^{2}

\frac{5 x ^{2} - 9 x + 20}{( 4 x + 1 ) ( 3 x - 4 )}

(tan (x) - csc (x))^{2} - 2 csc (x)

What is (\partial)/(\partial x)((y)(10-y-2x)) ?
The answer to (\partial)/(\partial x)((y)(10-y-2x)) is -2y