What is 2(2+log_{2}(375)) ?

The solution to 2(2+log_{2}(375)) is 4+2log_{2}(375)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 2(2+log_{2}(375))

simplify

2 (2 + lo g_{2} (375))

4 + 2 lo g_{2} (375)

Decimal Notation

21.10149 \dots

Solution steps

2 (2 + lo g_{2} (375))

Apply the distributive law:

a (b + c) = ab + a c

2 (2 + lo g_{2} (375)) = 2 \cdot 2 + 2 lo g_{2} (375)

= 2 \cdot 2 + 2 lo g_{2} (375)

Multiply the numbers:

2 \cdot 2 = 4

= 4 + 2 lo g_{2} (375)

20 (\frac{1}{2} x 16 - \frac{1}{4} x^{2})

\frac{1}{6} (1 + e^{2 x})^{3}

(1 + 5 sin (t)) \cdot (5 cos (t))

4 (- 2 x + 2 = 88)

(- 2 cos (u) sin (v) - cos^{2} (u) sin (v))^{2}

What is 2(2+log_{2}(375)) ?
The solution to 2(2+log_{2}(375)) is 4+2log_{2}(375)