What is expand 1/((x^2-2x)^2) ?

The solution to expand 1/((x^2-2x)^2) is 1/(x^4-4x^3+4x^2)

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expand 1/((x^2-2x)^2)

expand

\frac{1}{( x ^{2} - 2 x ) ^{2}}

\frac{1}{x ^{4} - 4 x ^{3} + 4 x ^{2}}

Solution steps

\frac{1}{( x ^{2} - 2 x ) ^{2}}

(x^{2} - 2 x)^{2} = x^{4} - 4 x^{3} + 4 x^{2}

= \frac{1}{x ^{4} - 4 x ^{3} + 4 x ^{2}}

(cos (x) + sin (x)) \cdot (- sin (x))

A (2, 0) B (1, - 1) C (- 1, 3)

(2 - r cos (θ))^{2}

6.46 + i (x + 1.71)

(\frac{1}{6} + \frac{5}{6})^{5}

What is expand 1/((x^2-2x)^2) ?
The solution to expand 1/((x^2-2x)^2) is 1/(x^4-4x^3+4x^2)