What is expand (2(2n-2x))/(n^2) ?

The solution to expand (2(2n-2x))/(n^2) is 4/n-(4x)/(n^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2(2n-2x))/(n^2)

expand

\frac{2 ( 2 n - 2 x )}{n ^{2}}

\frac{4}{n} - \frac{4 x}{n ^{2}}

Solution steps

\frac{2 ( 2 n - 2 x )}{n ^{2}}

Expand

2 (2 n - 2 x) : 4 n - 4 x

= \frac{4 n - 4 x}{n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 n - 4 x}{n ^{2}} = \frac{4 n}{n ^{2}} - \frac{4 x}{n ^{2}}

= \frac{4 n}{n ^{2}} - \frac{4 x}{n ^{2}}

Cancel

\frac{4 n}{n ^{2}} : \frac{4}{n}

= \frac{4}{n} - \frac{4 x}{n ^{2}}

- 1 (3 x + 3 y = 24)

\frac{2}{x ( x + 5 a ) ( x + 6 a )}

(2 x^{2} t - 2 x^{3}) d t

(x^{2} - 2 u^{2} x^{2}) d x

\frac{1 - e ^{- s}}{s ( s ^{2} - 4 s - 45 )}

What is expand (2(2n-2x))/(n^2) ?
The solution to expand (2(2n-2x))/(n^2) is 4/n-(4x)/(n^2)