What is expand ((4)^{-3})/(8^{-2)} ?

The solution to expand ((4)^{-3})/(8^{-2)} is 1

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expand ((4)^{-3})/(8^{-2)}

expand

\frac{( 4 ) ^{- 3}}{8 ^{- 2}}

1

Solution steps

\frac{4 ^{- 3}}{8 ^{- 2}}

Factor

4^{- 3} : \frac{1}{2 ^{6}}

Factor

8^{- 2} : \frac{1}{2 ^{6}}

= \frac{\frac{1}{2 ^{6}}}{\frac{1}{2 ^{6}}}

Cancel the common factor:

\frac{1}{2 ^{6}}

= 1

\frac{( 3 + 4 j ) ( 1 - 2 j )}{2 j + 4}

(4 - x) ln (x + 5)

(x - 2 + 1)^{2}

\frac{( s + 2 )}{s ( s + 1 ) ( s + 3 ) ( s + 5 )}

(7 + \frac{i}{n})^{2}

What is expand ((4)^{-3})/(8^{-2)} ?
The solution to expand ((4)^{-3})/(8^{-2)} is 1