What is expand 1/4 (2-2/3 z)^4 ?

The solution to expand 1/4 (2-2/3 z)^4 is 4-(16z)/3+(8z^2)/3-(16z^3)/(27)+(4z^4)/(81)

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expand 1/4 (2-2/3 z)^4

expand

\frac{1}{4} (2 - \frac{2}{3} z)^{4}

4 - \frac{16 z}{3} + \frac{8 z ^{2}}{3} - \frac{16 z ^{3}}{27} + \frac{4 z ^{4}}{81}

Solution steps

\frac{1}{4} (2 - \frac{2}{3} z)^{4}

Expand

(2 - \frac{2}{3} z)^{4} : 16 - \frac{64 z}{3} + \frac{32 z ^{2}}{3} - \frac{64 z ^{3}}{27} + \frac{16 z ^{4}}{81}

= \frac{1}{4} (16 - \frac{64 z}{3} + \frac{32 z ^{2}}{3} - \frac{64 z ^{3}}{27} + \frac{16 z ^{4}}{81})

Distribute parentheses

= \frac{1}{4} \cdot 16 + \frac{1}{4} (- \frac{64 z}{3}) + \frac{1}{4} \cdot \frac{32 z ^{2}}{3} + \frac{1}{4} (- \frac{64 z ^{3}}{27}) + \frac{1}{4} \cdot \frac{16 z ^{4}}{81}

Simplify

\frac{1}{4} \cdot 16 + \frac{1}{4} (- \frac{64 z}{3}) + \frac{1}{4} \cdot \frac{32 z ^{2}}{3} + \frac{1}{4} (- \frac{64 z ^{3}}{27}) + \frac{1}{4} \cdot \frac{16 z ^{4}}{81} : 4 - \frac{16 z}{3} + \frac{8 z ^{2}}{3} - \frac{16 z ^{3}}{27} + \frac{4 z ^{4}}{81}

= 4 - \frac{16 z}{3} + \frac{8 z ^{2}}{3} - \frac{16 z ^{3}}{27} + \frac{4 z ^{4}}{81}

(2 sin (y) - 6 y^{2} x) \cdot d x + (2 x cos (y) - 6 x^{2} y) \cdot d y

\frac{5 s - 2}{s ^{2} ( s + 2 ) ( s - 1 )}

\frac{B ^{2}}{4 A ^{2}} + (- h^{2} + \frac{C}{A})^{2} - - h^{2} + \frac{C}{A}

- 9 (x + 3)^{2}

cos (5 x) sin (x) + sin (5 x) (- cos (x) + 1)

What is expand 1/4 (2-2/3 z)^4 ?
The solution to expand 1/4 (2-2/3 z)^4 is 4-(16z)/3+(8z^2)/3-(16z^3)/(27)+(4z^4)/(81)