What is (7+sin(θ))^2+cos^2(θ) ?

The solution to (7+sin(θ))^2+cos^2(θ) is 14sin(θ)+50

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simplify (7+sin(θ))^2+cos^2(θ)

simplify

(7 + sin (θ))^{2} + cos^{2} (θ)

14 sin (θ) + 50

Solution steps

(7 + sin (θ))^{2} + cos^{2} (θ)

Expand

(7 + sin (θ))^{2} : 49 + 14 sin (θ) + sin^{2} (θ)

= 49 + 14 sin (θ) + sin^{2} (θ) + cos^{2} (θ)

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= 14 sin (θ) + 49 + 1

Add the numbers:

49 + 1 = 50

= 14 sin (θ) + 50

(\frac{( t ^{6} )}{15} + \frac{( 3 t ^{5} )}{25}) t^{2}

\frac{1}{( s + 1 ) ( s - 2 )}

(tan (θ) + sec (θ))^{2}

- \frac{2 ( x ^{2} - 5 x + 3 )}{ln ( 5 ) ( 2 x - 1 ) ( x + 1 ) ( x - 1 )}

\frac{x ^{2}}{( x - 1 ) ( x + 1 ) ^{2}}

What is (7+sin(θ))^2+cos^2(θ) ?
The solution to (7+sin(θ))^2+cos^2(θ) is 14sin(θ)+50