What is expand-sin(x)(1+tan(x)) ?

The solution to expand-sin(x)(1+tan(x)) is -sin(x)-sin(x)tan(x)

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expand-sin(x)(1+tan(x))

expand

- sin (x) (1 + tan (x))

- sin (x) - sin (x) tan (x)

Solution steps

- sin (x) (1 + tan (x))

Apply the distributive law:

a (b + c) = ab + a c

- sin (x) (1 + tan (x)) = - sin (x) \cdot 1 - sin (x) tan (x)

= - sin (x) \cdot 1 - sin (x) tan (x)

Apply rule:

a \cdot 1 = a

- sin (x) \cdot 1 = - sin (x)

= - sin (x) - sin (x) tan (x)

- 1.5 (cos (0.25 t^{2}) - 0.5 t^{2} sin (0.25 t^{2}))

\frac{( a + bi ) ^{6}}{( a - bi ) ^{2}}

(cos (ln (x)) + sin (ln (x)))^{2}

(1 - \frac{1 - cos ( x π )}{2}) 1 0^{\frac{x}{2}}

\frac{1}{8} e^{4 x} (- 4 e^{- 4 t} t - e^{- 4 t})

What is expand-sin(x)(1+tan(x)) ?
The solution to expand-sin(x)(1+tan(x)) is -sin(x)-sin(x)tan(x)