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Popular >

simplify (i+2)^4

Solution

simplify

(i + 2)^{4}

Solution

- 7 + 24 i

Solution steps

(i + 2)^{4}

Apply binomial theorem:

(a + b)^{n} = i = 0 \sum n (i n) a^{(n - i)} b^{i}

a = i, b = 2

= i = 0 \sum 4 (i 4) i^{(4 - i)} \cdot 2^{i}

Expand summation

= \frac{4 !}{0 ! ( 4 - 0 ) !} i^{4} \cdot 2^{0} + \frac{4 !}{1 ! ( 4 - 1 ) !} i^{3} \cdot 2^{1} + \frac{4 !}{2 ! ( 4 - 2 ) !} i^{2} \cdot 2^{2} + \frac{4 !}{3 ! ( 4 - 3 ) !} i^{1} \cdot 2^{3} + \frac{4 !}{4 ! ( 4 - 4 ) !} i^{0} \cdot 2^{4}

Simplify

\frac{4 !}{0 ! ( 4 - 0 ) !} i^{4} \cdot 2^{0} : i^{4}

Simplify

\frac{4 !}{1 ! ( 4 - 1 ) !} i^{3} \cdot 2^{1} : 8 i^{3}

Simplify

\frac{4 !}{2 ! ( 4 - 2 ) !} i^{2} \cdot 2^{2} : 24 i^{2}

Simplify

\frac{4 !}{3 ! ( 4 - 3 ) !} i^{1} \cdot 2^{3} : 32 i

Simplify

\frac{4 !}{4 ! ( 4 - 4 ) !} i^{0} \cdot 2^{4} : 16

= i^{4} + 8 i^{3} + 24 i^{2} + 32 i + 16

Simplify

i^{4} + 8 i^{3} + 24 i^{2} + 32 i + 16 : 24 i - 7

= 24 i - 7

Rewrite in standard complex form:

- 7 + 24 i

= - 7 + 24 i

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expand ((x+8)(x-6))/2 expand

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Frequently Asked Questions (FAQ)

What is (i+2)^4 ?
The solution to (i+2)^4 is -7+24i