What is 1/2 (arcsin(x-1)+1/2 sin(2arcsin(x-1))) ?

The solution to 1/2 (arcsin(x-1)+1/2 sin(2arcsin(x-1))) is (arcsin(x-1)+1/2 sin(2arcsin(x-1)))/2

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simplify 1/2 (arcsin(x-1)+1/2 sin(2arcsin(x-1)))

simplify

\frac{1}{2} (arcsin (x - 1) + \frac{1}{2} sin (2 arcsin (x - 1)))

\frac{arcsin ( x - 1 ) + \frac{1}{2} sin ( 2 arcsin ( x - 1 ) )}{2}

Solution steps

\frac{1}{2} (arcsin (x - 1) + \frac{1}{2} sin (2 arcsin (x - 1)))

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( arcsin ( x - 1 ) + \frac{1}{2} sin ( 2 arcsin ( x - 1 ) ) )}{2}

Apply rule:

1 \cdot a = a

1 \cdot (arcsin (x - 1) + \frac{1}{2} sin (2 arcsin (x - 1))) = (arcsin (x - 1) + \frac{1}{2} sin (2 arcsin (x - 1)))

= \frac{arcsin ( x - 1 ) + \frac{1}{2} sin ( 2 arcsin ( x - 1 ) )}{2}

\frac{x ^{3}}{4} (\frac{3}{x} - sin (\frac{3}{x}))

(9 u^{2}, - v, 64 u^{3}) \cdot (3, - 4, 0)

\frac{7 s + 33}{s ( s ^{2} - 2 s + 17 )}

(x + \frac{1}{3}) (x - \frac{1}{2}) (2 - x)

(e^{8 x} + 2)^{2}

What is 1/2 (arcsin(x-1)+1/2 sin(2arcsin(x-1))) ?
The solution to 1/2 (arcsin(x-1)+1/2 sin(2arcsin(x-1))) is (arcsin(x-1)+1/2 sin(2arcsin(x-1)))/2