What is expand (4-4sin(θ))^3 ?

The solution to expand (4-4sin(θ))^3 is 64-192sin(θ)+192sin^2(θ)-64sin^3(θ)

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expand (4-4sin(θ))^3

expand

(4 - 4 sin (θ))^{3}

64 - 192 sin (θ) + 192 sin^{2} (θ) - 64 sin^{3} (θ)

Solution steps

(4 - 4 sin (θ))^{3}

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(4 - 4 sin (θ))^{3} = 4^{3} - 3 \cdot 4^{2} \cdot 4 sin (θ) + 3 \cdot 4 (4 sin (θ))^{2} - (4 sin (θ))^{3}

= 4^{3} - 3 \cdot 4^{2} \cdot 4 sin (θ) + 3 \cdot 4 (4 sin (θ))^{2} - (4 sin (θ))^{3}

Simplify

4^{3} - 3 \cdot 4^{2} \cdot 4 sin (θ) + 3 \cdot 4 (4 sin (θ))^{2} - (4 sin (θ))^{3} : 64 - 192 sin (θ) + 192 sin^{2} (θ) - 64 sin^{3} (θ)

= 64 - 192 sin (θ) + 192 sin^{2} (θ) - 64 sin^{3} (θ)

\frac{( x - 0 ) ( x - 1 ) ( x - 2 ) ( x - 6 )}{- 60}

\frac{( s + 1 ) ( s - 1 )}{( s ^{2} + 1 )}

2 (3 x - 2 = 2)

(\frac{2 + x}{( 10 x ^{2} - 1 )}) (1000 x^{6} - 1)

\frac{48 x ^{2}}{( x - 15 ) ( x + 5 ) ^{2}}

What is expand (4-4sin(θ))^3 ?
The solution to expand (4-4sin(θ))^3 is 64-192sin(θ)+192sin^2(θ)-64sin^3(θ)