What is expand (2x-6)/(3(x^2-6x+5)^{2/3)} ?

The solution to expand (2x-6)/(3(x^2-6x+5)^{2/3)} is (2x)/(3(x^2-6x+5)^{2/3)}-2/((x^2-6x+5)^{2/3)}

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expand (2x-6)/(3(x^2-6x+5)^{2/3)}

expand

\frac{2 x - 6}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}}

\frac{2 x}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}} - \frac{2}{( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}}

Solution steps

\frac{2 x - 6}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x - 6}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}} = \frac{2 x}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}} - \frac{6}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}}

= \frac{2 x}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}} - \frac{6}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}}

Divide the numbers:

\frac{6}{3} = 2

= \frac{2 x}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}} - \frac{2}{( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}}

10 [lo g_{10} (\frac{I}{1 0 ^{- 12}})]

(2 p - 0.8) (2 p - 0, 5)

(3 x - \frac{1}{3})^{3}

\frac{d ^{3}}{d x ^{3}} ((y) (5 x^{4} - x^{3} + 2 x))

What is expand (2x-6)/(3(x^2-6x+5)^{2/3)} ?
The solution to expand (2x-6)/(3(x^2-6x+5)^{2/3)} is (2x)/(3(x^2-6x+5)^{2/3)}-2/((x^2-6x+5)^{2/3)}