What are the solutions to the equation x^2+20x+500=0 ?

The solutions to the equation x^2+20x+500=0 are x=-10+20i,x=-10-20i

Find the zeros of x^2+20x+500=0

The zeros of x^2+20x+500=0 are x=-10+20i,x=-10-20i

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x^{2} + 20 x + 500 = 0

x = - 10 + 20 i, x = - 10 - 20 i

Solution steps

x^{2} + 20 x + 500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 500}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 500 : 40 i

x_{1, 2} = \frac{- 20 \pm 40 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 40 i}{2 \cdot 1}, x_{2} = \frac{- 20 - 40 i}{2 \cdot 1}

x = \frac{- 20 + 40 i}{2 \cdot 1} : - 10 + 20 i

x = \frac{- 20 - 40 i}{2 \cdot 1} : - 10 - 20 i

The solutions to the quadratic equation are:

x = - 10 + 20 i, x = - 10 - 20 i

- 5 ∣ x + 1 ∣ = - 10

x^{5} + 5 x^{4} + 5 x^{3} - 5 x^{2} - 6 x

3 ab + ab c

- 2 + 3 (- 4) \geq \frac{1}{4}

3 x - 1 \leq 3

What are the solutions to the equation x^2+20x+500=0 ?
The solutions to the equation x^2+20x+500=0 are x=-10+20i,x=-10-20i
Find the zeros of x^2+20x+500=0
The zeros of x^2+20x+500=0 are x=-10+20i,x=-10-20i