What is expand (2x-5)/((2x-4)(x-4)(x-1)) ?

The solution to expand (2x-5)/((2x-4)(x-4)(x-1)) is (2x-5)/(2x^3-14x^2+28x-16)

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expand (2x-5)/((2x-4)(x-4)(x-1))

expand

\frac{2 x - 5}{( 2 x - 4 ) ( x - 4 ) ( x - 1 )}

\frac{2 x - 5}{2 x ^{3} - 14 x ^{2} + 28 x - 16}

Solution steps

\frac{2 x - 5}{( 2 x - 4 ) ( x - 4 ) ( x - 1 )}

Expand

(2 x - 4) (x - 4) (x - 1) : 2 x^{3} - 14 x^{2} + 28 x - 16

= \frac{2 x - 5}{2 x ^{3} - 14 x ^{2} + 28 x - 16}

12 (\frac{3 π ^{3}}{2 x ^{2}} - \frac{π ^{5}}{20 x ^{4}})

1 n (5 e^{2 x})

\frac{d ^{2}}{d x ^{2}} ((y) (2 + 0.1 (x - 2) e^{- x + 4}))

(d s + e) s^{2}

\frac{4 ( x ^{2} + 1 )}{x ^{2} - 6 x + 9}

What is expand (2x-5)/((2x-4)(x-4)(x-1)) ?
The solution to expand (2x-5)/((2x-4)(x-4)(x-1)) is (2x-5)/(2x^3-14x^2+28x-16)