What is expand (ycos(x)+1)dx+sin(x)dy ?

The solution to expand (ycos(x)+1)dx+sin(x)dy is ycos(x)dx+dx+sin(x)dy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (ycos(x)+1)dx+sin(x)dy

expand

(y cos (x) + 1) d x + sin (x) d y

y cos (x) d x + d x + sin (x) d y

Solution steps

(y cos (x) + 1) d x + sin (x) d y

Expand

d x (y cos (x) + 1) : y cos (x) d x + d x

= y cos (x) d x + d x + sin (x) d y

\frac{( p ( 424 - p ) ^{2} )}{150}

(3 x^{2} - 2 x + 1) l e f t (x^{3} + 2 x^{2})

(- 3 + 3 i 3)^{5}

\frac{4 π ( c - a ) ( b - c ) EF}{E ( b - c ) + F ( c - a )}

3 (x - 13) (x + 13) (x - 1)^{2}

What is expand (ycos(x)+1)dx+sin(x)dy ?
The solution to expand (ycos(x)+1)dx+sin(x)dy is ycos(x)dx+dx+sin(x)dy