What is expand 2cos(t)(2sin(t)-9tan(t)) ?

The solution to expand 2cos(t)(2sin(t)-9tan(t)) is 4cos(t)sin(t)-18sin(t)

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expand 2cos(t)(2sin(t)-9tan(t))

expand

2 cos (t) (2 sin (t) - 9 tan (t))

4 cos (t) sin (t) - 18 sin (t)

Solution steps

2 cos (t) (2 sin (t) - 9 tan (t))

Apply the distributive law:

a (b - c) = ab - a c

2 cos (t) (2 sin (t) - 9 tan (t)) = 2 cos (t) \cdot 2 sin (t) - 2 cos (t) \cdot 9 tan (t)

= 2 cos (t) \cdot 2 sin (t) - 2 cos (t) \cdot 9 tan (t)

Simplify

2 cos (t) \cdot 2 sin (t) - 2 cos (t) \cdot 9 tan (t) : 4 cos (t) sin (t) - 18 sin (t)

= 4 cos (t) sin (t) - 18 sin (t)

\frac{4 ( n + 1 )}{n}

P (0, - 4) Q (- 3, 0)

\frac{1}{x ( x - a ) ( x - b )}

\frac{3 x ( x - 4 )}{2 x} - 7

\frac{1}{36} y (1 - y)

What is expand 2cos(t)(2sin(t)-9tan(t)) ?
The solution to expand 2cos(t)(2sin(t)-9tan(t)) is 4cos(t)sin(t)-18sin(t)