What is expand-(4(-8x+3))/(e^{4x)} ?

The solution to expand-(4(-8x+3))/(e^{4x)} is (32x)/(e^{4x)}-(12)/(e^{4x)}

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expand-(4(-8x+3))/(e^{4x)}

expand

- \frac{4 ( - 8 x + 3 )}{e ^{4 x}}

\frac{32 x}{e ^{4 x}} - \frac{12}{e ^{4 x}}

Solution steps

- \frac{4 ( - 8 x + 3 )}{e ^{4 x}}

Expand

4 (- 8 x + 3) : - 32 x + 12

= - \frac{- 32 x + 12}{e ^{4 x}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 32 x + 12}{e ^{4 x}} = - (- \frac{32 x}{e ^{4 x}}) - (\frac{12}{e ^{4 x}})

= - (- \frac{32 x}{e ^{4 x}}) - (\frac{12}{e ^{4 x}})

Remove parentheses:

(a) = a, - (- a) = a

= \frac{32 x}{e ^{4 x}} - \frac{12}{e ^{4 x}}

2 (1 - \frac{2}{X ^{2} + 2})

\frac{2 \cdot x}{2 \cdot x}

(2 + \frac{1}{4} x)^{8} (4 x^{2} - 12 + \frac{9}{x ^{2}})

(x + 3) (x^{2} + 3)

What is expand-(4(-8x+3))/(e^{4x)} ?
The solution to expand-(4(-8x+3))/(e^{4x)} is (32x)/(e^{4x)}-(12)/(e^{4x)}