What is 4t(x)x^{''}+(t(x)-8)x^'-x ?

The solution to 4t(x)x^{''}+(t(x)-8)x^'-x is 4tx^{1+'^2}+x^'(tx-8)-x

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simplify 4t(x)x^{''}+(t(x)-8)x^'-x

simplify

4 t (x) x^{^{''}} + (t (x) - 8) x^{^{'}} - x

4 t x^{1 +'^{2}} + x^{'} (t x - 8) - x

Solution steps

4 t (x) x^{^{''}} + (t (x) - 8) x^{^{'}} - x

Remove parentheses:

(a) = a

= 4 t x x^{^{^{''}}} + (t x - 8) x^{^{^{'}}} - x

2 (6 + 21)

\frac{( x - 1 ) ( x + 3 )}{( x + 1 ) ^{2}}

\frac{10 x ^{2} + 20 x + 45}{( x + 4 ) ( x ^{2} + 9 )}

(0.5 - \frac{3}{2} i)^{4}

e^{x} (6 x - 3 x^{2})

What is 4t(x)x^{''}+(t(x)-8)x^'-x ?
The solution to 4t(x)x^{''}+(t(x)-8)x^'-x is 4tx^{1+'^2}+x^'(tx-8)-x