What is expand (log_{10}(x)(x^2+6)-1)/2 ?

The solution to expand (log_{10}(x)(x^2+6)-1)/2 is (x^2log_{10}(x))/2+3log_{10}(x)-1/2

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expand (log_{10}(x)(x^2+6)-1)/2

expand

\frac{lo g _{10} ( x ) ( x ^{2} + 6 ) - 1}{2}

\frac{x ^{2} lo g _{10} ( x )}{2} + 3 lo g_{10} (x) - \frac{1}{2}

Solution steps

\frac{lo g _{10} ( x ) ( x ^{2} + 6 ) - 1}{2}

Expand

lo g_{10} (x) (x^{2} + 6) - 1 : x^{2} lo g_{10} (x) + 6 lo g_{10} (x) - 1

= \frac{x ^{2} lo g _{10} ( x ) + 6 lo g _{10} ( x ) - 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} lo g _{10} ( x ) + 6 lo g _{10} ( x ) - 1}{2} = \frac{x ^{2} lo g _{10} ( x )}{2} + \frac{6 lo g _{10} ( x )}{2} - \frac{1}{2}

= \frac{x ^{2} lo g _{10} ( x )}{2} + \frac{6 lo g _{10} ( x )}{2} - \frac{1}{2}

Divide the numbers:

\frac{6}{2} = 3

= \frac{x ^{2} lo g _{10} ( x )}{2} + 3 lo g_{10} (x) - \frac{1}{2}

(2 + 5) (3 + 7)

\frac{( 3 - 2 j ) ( 8 + 10 j )}{( 11 + 8 i )}

\frac{( 2 - x ) ^{3} \cdot ( 9 - x ) ^{5}}{( x ^{2} + 8 ) ^{2}}

\frac{7 ( n + 1 ) ^{2}}{4 n}

(x - 3) (x + 3) (x - 2) (x + 2)

What is expand (log_{10}(x)(x^2+6)-1)/2 ?
The solution to expand (log_{10}(x)(x^2+6)-1)/2 is (x^2log_{10}(x))/2+3log_{10}(x)-1/2