What is expand ((x+1)x^2(x-1)^2)/4 ?

The solution to expand ((x+1)x^2(x-1)^2)/4 is (x^5)/4-(x^4)/4-(x^3)/4+(x^2)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x+1)x^2(x-1)^2)/4

expand

\frac{( x + 1 ) x ^{2} ( x - 1 ) ^{2}}{4}

\frac{x ^{5}}{4} - \frac{x ^{4}}{4} - \frac{x ^{3}}{4} + \frac{x ^{2}}{4}

Solution steps

\frac{( x + 1 ) x ^{2} ( x - 1 ) ^{2}}{4}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{x ^{2} ( x + 1 ) ( x ^{2} - 2 x + 1 )}{4}

Expand

(x + 1) x^{2} (x^{2} - 2 x + 1) : x^{5} - x^{4} - x^{3} + x^{2}

= \frac{x ^{5} - x ^{4} - x ^{3} + x ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{5} - x ^{4} - x ^{3} + x ^{2}}{4} = \frac{x ^{5}}{4} - \frac{x ^{4}}{4} - \frac{x ^{3}}{4} + \frac{x ^{2}}{4}

= \frac{x ^{5}}{4} - \frac{x ^{4}}{4} - \frac{x ^{3}}{4} + \frac{x ^{2}}{4}

(4 - r cos (θ) - r sin (θ))^{2}

3 (4 + 2)

\frac{115 ( 80 j + 13 )}{80 j + 36}

(x + 1) e

\frac{2 - 2 e ^{- 4 s} + 6 s}{s ( s - 1 )}

What is expand ((x+1)x^2(x-1)^2)/4 ?
The solution to expand ((x+1)x^2(x-1)^2)/4 is (x^5)/4-(x^4)/4-(x^3)/4+(x^2)/4